2006年08月02日 星期三 03:58
我建立了一个与系统auth_user表与Profile表OneToOne的关系,可是我测试在后台添加一个user后,并不会profile列出相应的ID来,大家帮忙看看,以下是Profile写的Models:
from django.db import models
from django.contrib.auth.models import User
from datetime import datetime
# Create your models here.
DEFAULT_DATE = datetime.now()
class Profile(models.Model):
user = models.OneToOneField(User)
#------个人资料----------
truename = models.CharField('真实姓名',maxlength=50,blank=True)
sex = models.CharField('性别',choices=(('M','男'),('F','女')),maxlength=1,radio_admin=True,blank=True,default='F')
idcard = models.IntegerField('身份证',maxlength=20,blank=True)
class Admin:
list_display = ('user', 'truename', 'sex', 'idcard')
def __str__(self):
return self.user.username
请大家看看这是什么问题?
2006年08月07日 星期一 11:00
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Django官方的做法(也是最流行的做法)是在setting.py中添加
AUTH_PROFILE_MODULE = 'Profile.Profile' #不是Profile.models.Profile
然后使用User的get_profile()来返回Profile.
但是按照默认的关系映射的方式来讲,直接使用每个Profile的实例对应对应的User
也是可以的。如同下面返回username那样:
def __str__(self):
return self.user.username
lendcomcn wrote:
> 我建立了一个与系统auth_user表与Profile表OneToOne的关系,可是我测试在后台
> 添加一个user后,并不会profile列出相应的ID来,大家帮忙看看,以下是Profile
> 写的Models:
>
> from django.db import models
> from django.contrib.auth.models import User
> from datetime import datetime
>
> # Create your models here.
> DEFAULT_DATE = datetime.now()
>
> class Profile(models.Model):
> user = models.OneToOneField(User)
>
> #------个人资料----------
> truename = models.CharField('真实姓名',maxlength=50,blank=True)
> sex = models.CharField('性别',choices=(('M','男'),('F','女')),maxlength=
> 1,radio_admin=True,blank=True,default='F')
> idcard = models.IntegerField('身份证',maxlength=20,blank=True)
>
> class Admin:
> list_display = ('user', 'truename', 'sex', 'idcard')
>
> def __str__(self):
> return self.user.username
>
> 请大家看看这是什么问题?
>
>
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