'\xff'*length_of_string就可以

======== 2004-03-17 12:00:14 您在来信中写道： ========

如何比较方便的获得"\xff\xff\xff\xff\xff.....\xff\xff"这种很多重复字符的字符串？
我现在的用法是 s = ''.zfill(length_of_string).replace('0', the_sub_string)
可以用，但想知道有没有更直接、更高效的用法？
谢谢！
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应该是'\\xff'*length_of_string
必须对\进行逃逸
  ----- Original Message ----- 
  From: 贾利亚 
  To: python-chinese at lists.python.cn 
  Sent: Wednesday, March 17, 2004 1:53 PM
  Subject: Re: [python-chinese] How to get a filled string?


  　　 '\xff'*length_of_string就可以

  ======== 2004-03-17 12:00:14 您在来信中写道： ========

          如何比较方便的获得"\xff\xff\xff\xff\xff.....\xff\xff"这种很多重复字符的字符串？
          我现在的用法是 s = ''.zfill(length_of_string).replace('0', the_sub_string)
          可以用，但想知道有没有更直接、更高效的用法？
          谢谢！
       





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